William Shepherd Bullock

1842–
Deposit, Sanford, Broome, New York, United States

The Life of William Shepherd

When William Shepherd Bullock was born in 1842, in Deposit, Sanford, Broome, New York, United States, his father, Jacob Bullock, was 31 and his mother, Harriet Edick, was 26. He married Mary E. Ross on 3 July 1866. He lived in Sanford, Broome, New York, United States for about 5 years and Windsor, Broome, New York, United States for about 5 years.

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Family Time Line

William Shepherd Bullock
1842–
Mary E. Ross
Marriage: 3 July 1866

Spouse and Children

MARRIAGE
3 July 1866
Manhattan, New York, New York

Parents and Siblings

siblings

(7)

    Male1836–Male

    Ester Bullock

    Female1839–Female

    Dan Bullock

    Male1841–Male

    Male1842–Male

    Maretta Bullock

    Female1844–Female

+2 More Children

World Events (8)

1846

Age 4

U.S. acquires vast tracts of Mexican territory in wake of Mexican War including California and New Mexico.
1863

Age 21

Abraham Lincoln issues Emancipation Proclamation, declaring slaves in Confederate states to be free.
1875 · A Treaty with Hawaii

Age 33

In the Mid 1870s, The United States sought out the Kingdom of Hawaii to make a free trade agreement. The Treaty gave the Hawaiians access to the United States agricultural markets and it gave the United States a part of land which later became Pearl Harbor.

Name Meaning

English: from Middle English bullok ‘bullock’ (Old English bulluc), referring to a young bull rather than a castrated one, probably applied as a nickname for an exuberant young man, or a metonymic occupational name for a keeper of bullocks.

Dictionary of American Family Names © Patrick Hanks 2003, 2006.

Possible Related Names

Sources (3)

  • Shepard Bullock in household of Jacob Bullock, "New York State Census, 1865"
  • Shepherd Bullock in household of Jacob Bullock, "United States Census, 1860"
  • Sheperd W Bullock in household of Jacob Bullock, "New York State Census, 1855"

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