George Carl O'Neall

19 June 1859–1 February 1909 (Age 49)
Newton, Jasper, Iowa, United States

The Life of George Carl

When George Carl O'Neall was born on 19 June 1859, in Newton, Jasper, Iowa, United States, his father, John Belton O'Neall, was 30 and his mother, Eliza "Lida" Helm, was 21. He married Loretta Helen Olive Wiley on 14 February 1884, in Jasper, Iowa, United States. He lived in Iowa, United States in 1870. He died on 1 February 1909, in Jasper, Missouri, United States, at the age of 49.

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Family Time Line

George Carl O'Neall
1859–1909
Loretta Helen Olive Wiley
1865–1922
Marriage: 14 February 1884

Spouse and Children

MARRIAGE
14 February 1884
Jasper, Iowa, United States

Parents and Siblings

siblings

(3)

World Events (8)

1860

Age 1

In 1860, the Pony Express used men riding on horseback to carry mail between St. Joseph, Missouri, and Sacramento, California.
1863

Age 4

Abraham Lincoln issues Emancipation Proclamation, declaring slaves in Confederate states to be free.
1875 · A Treaty with Hawaii

Age 16

In the Mid 1870s, The United States sought out the Kingdom of Hawaii to make a free trade agreement. The Treaty gave the Hawaiians access to the United States agricultural markets and it gave the United States a part of land which later became Pearl Harbor.

Name Meaning

Irish: variant spelling of O’Neill .

Dictionary of American Family Names © Patrick Hanks 2003, 2006.

Possible Related Names

Sources (3)

  • George C Oneall in household of John B Oneall, "United States Census, 1870"
  • George C Oneall in household of John B Oneall, "United States Census, 1870"
  • George Carroll O Neall, "Iowa, County Marriages, 1838-1934"

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