Brief Life History of Abraham Riley
When Abraham Riley Hollenbeck was born on 5 February 1856, in Lexington, Lexington Township, Scott, Indiana, United States, his father, James Parry Hollenbeck, was 29 and his mother, Parthenia Jane Horner, was 27. He married Amelia C Robinett on 16 January 1879, in Clark, Indiana, United States. They were the parents of at least 3 sons and 2 daughters. He lived in Washington Township, Clark, Indiana, United States in 1910 and Indianapolis, Marion, Indiana, United States in 1920. He died on 11 January 1928, in West Palm Beach, Dade, Florida, United States, at the age of 71, and was buried in New Washington, Washington Township, Clark, Indiana, United States.
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Family Time Line
Sources (14)
- Abram R Hollenback, "United States Census, 1900"
- Abraham Hollenbeck in entry for James E Hollenbeck and Helen C Holsinger, "Indiana Marriages, 1811-2007"
- Abram Riley Hollenbeck, "Florida Deaths, 1877-1939"
Spouse and Children
1856–1928 Male
1860–1898 Female
Children (5)
1879– Female
1887–1973 Female
1889–1944 Male
1892–1973 Male
1892– Male
Parents and Siblings
1826–1863 Male
1830–1892 Female
Siblings (4)
1852–1854 Female
1854– Female
1856–1928 Male
1863–1943 Male
World Events (8)
1861
Age 5
1863
Age 7
1875 · A Treaty with Hawaii
Age 19
Name Meaning
North German: habitational name from a place so named near Hamburg or from Hollenbek near Ratzeburg.
Dictionary of American Family Names © Patrick Hanks 2003, 2006.
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